Dividing Whole Numbers

How to divide with whole numbers

In order to learn who to divide with whole numbers, you first need to know how to multiply. For example: 2 x 2 = 4 so say your problem is 4 /2 you would need to know how many times that 2 goes in to 4. And the answer would be 2. Examples   4 x 2 = 8,    4/8 =2

                                                                                                  5 x 7 =35,  5/35 = 7                         

     8                    32                4  because... 8x4 is 32

Division is Arithmetic. the operation inverse to multiplication; the finding of a quantity, the quotient, that when multiplied by a given quantity, the divisor, gives another given quantity, the dividend; the process of ascertaining how many times one number or quantity is contained in another.

To look at more divison problems you can go here http://aaaknow.com/div.htm#topic8 and practice some more.

http://www.themathpage.com/ARITH/divide-whole-numbers.htm                                                                               

1. When we write the division box, where do we write the divisor?
2. How do we do short division?
3. When the dividend is a decimal, where does the point go in the quotient?

   Section 2

4. How do we round off, or approximate, a decimal to a given number of decimal places?
5. How do we express the quotient as a decimal?

Dividend ÷ Divisor = Quotient

Example.   Using the division box, write 1 ÷ 4.  (There is nothing to calculate.)

Answer.  4 is the divisor.  It goes outside the box.

Before going on to short division, the student should be clear about division with remainder.

"7 goes into 25 three (3) times (21) with 4 left over."

Write the remainder 4 beside the 2.  Continue:

"7 goes into 42 six (6) times exactly."

Begin, "5 goes into 17 three (3) times (15) with 2 left over."

Write 3 over the 7 (not over the 1), and write the remainder 2 next to the 9.

Continue: "5 goes into 29 five (5) times (25) with 4 left over.

Write 5 over the 9, and write the remainder 4 next to the 8.

Finally, "5 goes into 48 nine (9) times (45) with 3 left over."

Write 9 over the 8.  The final remainder is 3.

This problem will illustrate the following point:

We will write a digit over the 1, then over the 6, then over the 0, and so on, until finally we write a digit over the 3.

Begin,

"4 goes into 21 five (5) times (20) with remainder 1 ."

Next, "4 goes into 16 four (4) times exactly."

Next, "4 goes into 0 zero (0)."

Whenever the partial dividend is less than the divisor

-- 0 is less than 4 -- write 0 in the quotient.

Next, we must write a digit over the 2:  "4 goes into 2 zero (0)."

Now the 2 remains.  It is the remainder.

Whenever the quotient is 0, that digit beneath it .

in the dividend is the remainder

"4 goes into 24 six (6) times exactly."

Finally, "4 goes into 3 zero (0)."

3 is the final remainder.

Again, whenever the quotient is 0, the digit beneath it in the dividend remains.