Pythagorean Identities :There are two types of identitties:
The following information was found at:http://coolmath.com/pythagoreanidentities.htm
Let's start with the Unit Circle:
Zooming in to get a better look, we can label the sides of our right triangle...
By the Pythagorean Theorem, we have that
Since this is a Unit Circle, we have
Substituting, gives us
(The first Pythagorean Identity)
Most people easily remember this first identity... But, often times, you'll need to remember the other two when you get to Calculus.
Here's an easy way to derive the next two, starting from the first one:
2) Divide everywhere by
Simplifying gives us the second Pythagorean Identity...
3) Divide everywhere by
Simplifying gives us the third and final Pythagorean Identity...
Theb following Explanatin of Power Series was found at:http://en.wikipedia.org/wiki/Power_series
Power series :
Any polynomial can be easily expressed as a power series around any center c, albeit one with most coefficients equal to zero. For instance, the polynomial f(x) = x2 + 2x + 3 can be written as a power series around the center c = 0 as
or around the center c = 1 as
or indeed around any other center c. One can view power series as being like "polynomials of infinite degree," although power series are not polynomials.
The geometric series formula
which is valid for | x | < 1, is one of the most important examples of a power series, as are the exponential function formula
and the sine formula
valid for all real x. These power series are also examples of Taylor series. However, there exist power series which are not the Taylor series of any function, for instance
Negative powers are not permitted in a power series, for instance is not considered a power series (although it is a Laurent series). Similarly, fractional powers such as x1 / 2 are not permitted (but see Puiseux series). The coefficients an are not allowed to depend on x, thus for instance:
- is not a power series.
[edit] Radius of convergence
A power series will converge for some values of the variable x (at least for x = c) and may diverge for others. There is always a number r with 0 ≤ r ≤ ∞ such that the series converges whenever |x − c| < r and diverges whenever |x − c| > r. The number r is called the radius of convergence of the power series; in general it is given as
or, equivalently,
(see limit superior and limit inferior). A fast way to compute it is
if this limit exists.
The series converges absolutely for |x - c| < r and converges uniformly on every compact subset of {x : |x − c| < r}.
For |x - c| = r, we cannot make any general statement on whether the series converges or diverges. However, Abel's theorem states that the sum of the series is continuous at x if the series converges at x.
Comments (10)
Anonymous said
at 10:09 am on Nov 5, 2007
umm... is there any content? nice links but you might want to acctully do something if you want any credit dude. =P
Anonymous said
at 10:21 am on Nov 5, 2007
umm you need more examples and stuff you r going to get a bad graae if you dont
Anonymous said
at 1:00 pm on Nov 5, 2007
i think you need to do some work but k...i don;t think you are going to get a very good grade but try harder come on it isn't that hard
Anonymous said
at 1:00 pm on Nov 5, 2007
i think you need to do some work but k...i don;t think you are going to get a very good grade but try harder come on it isn't that hard
Anonymous said
at 2:44 pm on Nov 5, 2007
you need allot of info, if you don't play on halo 3 this weekend you MAY catch up.
Anonymous said
at 2:45 pm on Nov 5, 2007
you need to work on ur page
Anonymous said
at 2:46 pm on Nov 5, 2007
You dont have enough info on your page. Except links. Links may be useful but YOU'RE supposed to teach us about pytahgorean therom
Anonymous said
at 7:22 pm on Nov 5, 2007
You need a lot more info pics and everything if you want to do good get started
Anonymous said
at 9:45 am on Nov 13, 2007
you need to do something dude the page is like due today
Anonymous said
at 10:32 pm on Nov 14, 2007
Nello, this really is not a good effort. I wish you had asked for help a while ago.
1 of 4 points.
1 of 12 total project points. Ouch.
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